Question

C/C++ 1. 1 - 1/3 + 1/5 - 1/7 +...+ (-1)n-1 1/2n-1+... 2. 1/1[4 + 1/2[5 + 1/3[6 + 1/4[7 +...+ 1/n(n + 3) +...

Answer 1

Ответ:

1.

#include <iostream>

using namespace std;

int main()

{

   double n, j = 1;

   long long i;

   cin >> n;

   for(i = 2; i <= n; i++)

       if(i % 2)

       j += (1.0/(2.0*i-1.0));

             else

             j -= (1.0/(2.0*i-1.0));

   cout << j << endl;

   return 0;

}

2.

#include <iostream>

using namespace std;

int main()

{

   double n, j = 0;

   long long i;

   cin >> n;

   for(i = 1; i <= n; i++)

       j += (1.0/(n*(n+3.0)));

   cout << j << endl;

   return 0;

}

Объяснение:

Answer 2

These two mathematical series can be implemented in C/C++ as follows:

1. To calculate the series 1 - 1/3 + 1/5 - 1/7 + ... + (-1)^(n-1) * 1/(2n-1):

cCopy code
#include <stdio.h>

int main() {
    int n;
    double result = 0.0;

    printf("Enter the value of n: ");
    scanf("%d", &n);

    for (int i = 1; i <= n; i++) {
        double term = 1.0 / (2 * i - 1);
        if (i % 2 == 0) {
            term = -term; // Alternate terms are subtracted
        }
        result += term;
    }

    printf("The result of the series is: %lf\n", result);

    return 0;
}

This code takes an input n, and then it calculates the series up to n terms, alternating the sign of each term based on its position in the series.

2. To calculate the series 1/1[4 + 1/2[5 + 1/3[6 + 1/4[7 + ... + 1/n(n + 3) + ...:

cCopy code
#include <stdio.h>

double nestedSeries(int n) {
    double result = 0.0;

    for (int i = n; i >= 1; i--) {
        result = (i + 3 + result) / i;
    }

    return result;
}

int main() {
    int n;
    
    printf("Enter the value of n: ");
    scanf("%d", &n);

    double seriesResult = nestedSeries(n);

    printf("The result of the nested series is: %lf\n", seriesResult);

    return 0;
}

This code defines a function nestedSeries that recursively calculates the nested series for a given value of n. It starts with the innermost term and works its way out. The main function takes an input n and then calls the nestedSeries function to calculate the result.