Question

For i in range(6): if i == 3: continue print (i)

Answer 1

код:

for i in range(6):

....if i == 3:

........continue

....print (i)

вывод:

0

1

2

4

5

Answer 2

The code you've provided is a Python for loop that iterates through a range of numbers from 0 to 5 (inclusive). When i is equal to 3, it encounters a continue statement, which causes the loop to skip the current iteration and move to the next one. Here's how the code behaves:

1. i is 0, which is not equal to 3, so it proceeds to the print(i) statement and prints 0.
2. i is 1, which is not equal to 3, so it proceeds to the print(i) statement and prints 1.
3. i is 2, which is not equal to 3, so it proceeds to the print(i) statement and prints 2.
4. i is 3, which is equal to 3, so it encounters the continue statement. This causes the loop to skip the rest of the code for this iteration and move to the next value of i.
5. i is 4, which is not equal to 3, so it proceeds to the print(i) statement and prints 4.
6. i is 5, which is not equal to 3, so it proceeds to the print(i) statement and prints 5.

As a result, the code will print:

Copy code
0
1
2
4
5

The number 3 is skipped due to the continue statement.