Question

ПОЖАЛУЙСТА ПОМОГИТЕ 1. Написать программу, которая выводит на экран в одной строке через пробел числа от 15 до 72 с шагом 3(15 18 21 ...), используя цикл while.

Answer 1

Ответ:

a=15

while a<=72:

print(a,end=' ')

a+=3

Объяснение:

отступы на скрине

Answer 2

Program to Print Numbers Using a While Loop in C++

Here's a program that uses a `while` loop to print numbers from 15 to 72 with a step of 3, all in one line separated by spaces:

#include

int main() {
    int num = 15;
    while (num <= 72) {
        std::cout << num << " ";
        num += 3;
    }
    return 0;
}

This program initializes the variable `num` to 15. It then enters a `while` loop that continues as long as `num` is less than or equal to 72. Inside the loop, it prints the value of `num` followed by a space using `std::cout`. After printing, it increments `num` by 3. The loop continues until `num` is no longer less than or equal to 72.

When you run this program, it will output the numbers from 15 to 72 with a step of 3, all in one line separated by spaces.

Note: The program assumes you are using C++ and have the necessary libraries included. Make sure to include the appropriate headers (`iostream` in this case) and use the correct namespace (`std`) for input/output operations.

I hope this helps! Let me know if you have any further questions.