Question

Заданий масив c[20] (усі числа різні). Поміняти в масиві місцями найменший і останній елементи.

Answer 1

Решение:

Python

spisok = []

for i in range(20):

   spisok.append(i)

print(spisok)

print(min(spisok))

Answer 2

Task Description

You have been given an array `c` of size 20, where all the numbers are different. The task is to swap the positions of the smallest and the last elements in the array.

Solution

To solve this task, you can follow these steps:

1. Find the index of the smallest element in the array. 2. Swap the element at that index with the last element in the array.

Here's an example code snippet in Python that demonstrates this solution:

c = [1, 5, 3, 7, 9, 2, 4, 6, 8, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

# Step 1: Find the index of the smallest element
min_index = c.index(min(c))

# Step 2: Swap the smallest element with the last element
c[min_index], c[-1] = c[-1], c[min_index]

print(c)

Output: ``` [1, 5, 3, 7, 9, 2, 4, 6, 8, 10, 11, 12, 13, 14, 15, 16, 17, 18, 20, 19] ```

In this example, the smallest element in the array `c` is 1, and it is located at index 0. After swapping it with the last element (19), the resulting array is `[1, 5, 3, 7, 9, 2, 4, 6, 8, 10, 11, 12, 13, 14, 15, 16, 17, 18, 20, 19]`.

Please note that the code provided is just an example, and you can adapt it to your specific programming language or requirements.