Question

Обчислити суму непарних чисел від 50 до 100 за допомогою операторів циклу

Answer 1

var

 sum, i: Integer;

begin

 sum := 0;

 i := 51;

 while i < 100 do begin

   sum := sum + i;

   i := i + 2;

 end;

 WriteLn(sum);

end.  

Answer 2

Calculating the Sum of Odd Numbers from 50 to 100 Using a Loop

To calculate the sum of odd numbers from 50 to 100 using a loop, we can use a simple loop structure to iterate through the numbers and add the odd ones to a running total. In this case, we'll use a "while" loop to achieve this.

Here's a simple Java code snippet to accomplish this:

public static void main(String[] args) {
    int sum = 0;
    int i = 50; // Start from 50
    while (i <= 100) {
        if (i % 2 != 0) { // Check if the number is odd
            sum += i; // Add the odd number to the sum
        }
        i++; // Move to the next number
    }
    System.out.println("The sum of odd numbers from 50 to 100 is: " + sum);
}

This code initializes a variable `sum` to 0 and a variable `i` to 50. It then enters a "while" loop that continues as long as `i` is less than or equal to 100. Within the loop, it checks if the current value of `i` is odd using the condition `i % 2 != 0`. If it is odd, it adds the value of `i` to the `sum`. After each iteration, it increments `i` by 1.

When the loop finishes, it prints out the total sum of the odd numbers from 50 to 100.

This code effectively calculates the sum of odd numbers within the specified range using a "while" loop.

Note: The provided code is a Java example for calculating the sum of odd numbers from 50 to 100 using a "while" loop.

I hope this helps! If you have any more questions or need further assistance, feel free to ask.