Question

Нужно найти минимальное число из массива и вывести его на экран. Массив A: array [1..5] of integer;

Answer 1

Var
  a: array [1..5] of integer;
  i: byte;
  k: integer := Integer.MaxValue;

begin
  for i := 1 to 5 do
    readln(a[i]);
  for i := 1 to 5 do
    k := Min(k, a[i]);
  writeln(k);
end.

Answer 2

Sure! Here's an example of how you can find the minimum number in the array A and display it on the screen using a simple algorithm:

pythonCopy code
A = [10, 5, 8, 3, 6]  # Example array

# Set the first element as the initial minimum
minimum = A[0]

# Iterate through the array starting from the second element
for num in A[1:]:
    # If the current number is smaller than the current minimum,
    # update the minimum
    if num < minimum:
        minimum = num

# Display the minimum number
print("The minimum number is:", minimum)

In this example, the array A contains five integers. The algorithm iterates through the array, compares each element with the current minimum, and updates the minimum if a smaller number is found. Finally, the minimum number is displayed on the screen.