Question

I := 3 a := 12 нц пока i<6 a := a + i i := i + 1 кц

Answer 1

До 1ой иттерации: i = 3; a = 12

До 2ой иттерации: i = 4; a = 15

До 3ьей: i = 5; a = 19

После 3ьей: i = 6; a = 24

Answer 2

It seems like you're trying to write a code snippet, but the syntax you provided is not clear. However, based on the pattern in your code, it seems like you want to initialize a variable I with the value 3 and another variable a with the value 12. Then you want to loop while i is less than 6, updating the value of a by adding i to it, and incrementing i by 1 in each iteration.

Assuming the correct syntax, here's a modified version of your code:

pythonCopy code
I = 3
a = 12

while I < 6:
    a = a + I
    I = I + 1

This code initializes I with 3 and a with 12. It then enters a loop that continues as long as I is less than 6. In each iteration, it adds the value of I to a and increments I by 1. Once I reaches 6, the loop exits.

After running this code, the final value of a will be 33.