Question

Определить молекулярную массу гена ДНК, кодирующий белок молекулярной массой 3400 усл. Ед.

Answer 1

Молекулярная масса одной аминокислоты -- 100 а.е.м

Найдем количество аминокислот:

1 аминокислота ----- 100 а.е.м
Х аминокислот ------ 3400 а.е.м

Решаем пропорцию:

$X= \frac{3400}{100} =34$ аминокислот в белке.

------------------------------------------------------------------------

В одной аминокислоте содержит 3 нуклеотида,тогда:

$34*3=102$ нуклеотидов в белке.

Так как молекула ДНК двухцепочная,то $102*2=204$ нуклеотидов в обоих цепях ДНК.

-------------------------------

Средняя масса одного нуклеотида равна 345 а.е.м

1 нуклеотид ----- 345 а.ем.
204 нуклеотидов --- Х а.е.м

Решаем:

$X = 204*345 =70380$ составляет молекулярная масса гена ДНК.

==================================================================

Answer 2

Calculating the molecular mass of a DNA gene encoding a protein with a molecular mass of 3400 Da

To calculate the molecular mass of the DNA gene encoding this protein, we first need to know some key facts:

DNA is made up of nucleotides that each have a specific molecular mass. The four nucleotides that make up DNA are adenine (A), thymine (T), cytosine (C), and guanine (G). A has a molecular mass of 135 Da, T has a molecular mass of 127 Da, C has a molecular mass of 111 Da, and G has a molecular mass of 151 Da.

The genetic code uses triplets of nucleotides (codons) to encode for each amino acid in a protein. Since there are 20 standard amino acids that make up proteins, and the genetic code uses triplets of nucleotides, we can calculate the minimum number of nucleotides needed to encode a protein of a given mass.

A typical protein is made of amino acids with an average molecular mass of 110 Da each. To encode a protein with a molecular mass of 3400 Da, we would need at least 3400/110 = 31 amino acids. Since the genetic code uses triplets, we would need a minimum of 31 * 3 = 93 nucleotides.

In reality, the gene would be longer to account for non-coding sequences. The actual length of the DNA gene would be longer than the minimum calculated above to include non-coding introns and other regulatory sequences. Without more specifics, we can estimate the molecular mass of the gene would be over 10000 Da to encode a protein of 3400 Da.