
Одна из цепочек фрагмента молекулы ДНК имеет такую последовательность нуклеотидов ЦГТГАТТТТГГТТГТА.
Какова будет структура фрагмента ДНК после репликации?

Ответы на вопрос




Structure of the DNA Fragment After Replication
The given DNA fragment sequence is "ЦГТГАТТТТГГТТГТА." To determine the structure of the DNA fragment after replication, we need to understand the process of DNA replication.
During DNA replication, the double-stranded DNA molecule unwinds and separates into two strands. Each separated strand serves as a template for the synthesis of a new complementary strand. The process is semi-conservative, meaning that each resulting DNA molecule consists of one original strand and one newly synthesized strand.
To determine the structure of the DNA fragment after replication, we need to identify the complementary base pairs for each nucleotide in the given sequence. In DNA, the complementary base pairs are adenine (A) with thymine (T) and cytosine (C) with guanine (G).
Given the sequence "ЦГТГАТТТТГГТТГТА," we can determine the complementary sequence by replacing each nucleotide with its complementary base pair:
Ц (C) -> Г (G) Г (G) -> Ц (C) Т (T) -> А (A) Г (G) -> Ц (C) А (A) -> Т (A) Т (T) -> А (A) Т (T) -> А (A) Т (T) -> А (A) Г (G) -> Ц (C) Т (T) -> А (A) Т (T) -> А (A) А (A) -> Т (A)
Therefore, the complementary sequence to "ЦГТГАТТТТГГТТГТА" is "ГЦАЦТААААЦЦААТ."
After replication, each of the original strands serves as a template for the synthesis of a new complementary strand. Therefore, the resulting structure of the DNA fragment after replication will consist of two identical double-stranded DNA molecules, with each molecule having one original strand and one newly synthesized strand. The complementary sequence "ГЦАЦТААААЦЦААТ" will pair with the original sequence "ЦГТГАТТТТГГТТГТА" to form the double-stranded DNA molecule.
Note: The given sequence contains characters that are not standard nucleotides (Ц, Г). If these characters represent specific nucleotides, please provide the corresponding nucleotides for a more accurate answer.


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