Question

Какое количество типов гамет будет образовываться у особи, имеющей генотип АаСс, если гены АС и ас наследуются сцеплено, а кроссинговер отсутвтвует?1)12)23)34)4

Answer 1

Так: 
Данная особь образует 4 типа гамет 
некроссоверные гаметы 
АС - 30% 
ас - 30% 
кроссоверные гаметы 
Ас - 15% 
аС - 15% 

Answer 2

Gamete Formation for an Individual with Genotype AaCc

If an individual has the genotype AaCc, and the genes AC and ac are inherited in linkage, with no crossing over, the number of types of gametes that will be formed can be determined.

The number of types of gametes formed can be calculated using the formula 2^n, where n is the number of heterozygous gene pairs.

In this case, the individual has two heterozygous gene pairs (Aa and Cc).

Using the formula 2^n, where n is the number of heterozygous gene pairs: 2^2 = 4

Therefore, the individual with the genotype AaCc, where the genes AC and ac are inherited in linkage and no crossing over occurs, will form 4 types of gametes.