Question

В одной цепи ДНК количество аденина составляет 19%, тимина-31%, гуанина-8%, цитозина-42%.Пользуясь правилами Чаргаффа, определите процентное содержание нуклеотидов в целом молекуле ДНК.___________в одному ланцюзі днк кількість аденіну становить 19%, тиміну- 31%, гуаніну-8%, цитозину- 42%.Користуючись правилами Чаргаффа, визначте процентний вміст нуклеотидів у цілій молекулі ДНК

Answer 1

По правилу Чаргаффа: А=Т, Г=Ц

1-я цепь ДНК: А-19%, Т-31%, Г-8%, Ц-42%

2-я цепь ДНК: Т-19%, А-31%, Ц-8%, Г-42%

А=(19%+31%)/2=25%

Т=25%

Г=(8%+42%)/2=25%

Ц=25%

Answer 2

According to Chargaff's rules, the amount of adenine (A) is equal to the amount of thymine (T), and the amount of guanine (G) is equal to the amount of cytosine (C) in a DNA molecule. Based on the given percentages, we can calculate the overall percentage of nucleotides in the DNA molecule.

The given percentages are as follows: - Adenine (A): 19% - Thymine (T): 31% - Guanine (G): 8% - Cytosine (C): 42%

To determine the overall percentage of nucleotides in the DNA molecule, we can add the percentages of A and T together, and the percentages of G and C together. Let's calculate it:

- A + T = 19% + 31% = 50% - G + C = 8% + 42% = 50%

According to Chargaff's rules, A + T = G + C in a DNA molecule. Therefore, the overall percentage of nucleotides in the DNA molecule is 50% for both A + T and G + C.

Overall Percentage of Nucleotides in the DNA Molecule:

- Adenine (A) + Thymine (T): 50% - Guanine (G) + Cytosine (C): 50%

Please let me know if there's anything else I can help you with!