Question

Ген карего цвета (К) доминирует над геном голубого цвета (к). Определите вероятность появления голубоглазых и кареглазых детей в следующих типах браков ПОМОГИТЕ СРОЧНО ПОЖАЛУЙСТА

Answer 1

Дано:
ген - K карие 
ген - к голубые
Найти:вероятность голубоглазых и кареглазых детей
Решение:
Р Kk  x  kk
G K k    k k
F1 Kk Kk kk kk
Ответ: вероятность рождения кареглазых детей 50%;вероятность голубоглазых 50%

Answer 2

Understanding the Inheritance Pattern

In this scenario, we are dealing with the inheritance of eye color, where the dominant gene for brown eye color (K) overrides the recessive gene for blue eye color (k). We want to determine the probability of having blue-eyed and brown-eyed children in the following types of marriages.

Inheritance Patterns and Probabilities

In a situation where one parent is homozygous dominant (KK) and the other is heterozygous (Kk), the possible genotypes of the offspring are KK and Kk. In this case, all the children will have brown eyes.

In a marriage between two heterozygous individuals (Kk x Kk), the possible genotypes of the offspring are KK, Kk, and kk. The probability of having a child with blue eyes (kk) is 25%, while the probability of having a child with brown eyes (KK or Kk) is 75%.

In a marriage between a homozygous recessive individual (kk) and a heterozygous individual (Kk), all the children will have brown eyes.

In summary, the probabilities of having blue-eyed and brown-eyed children in the mentioned types of marriages are as follows: - Homozygous dominant x Heterozygous: 100% brown-eyed children - Heterozygous x Heterozygous: 25% blue-eyed children, 75% brown-eyed children - Homozygous recessive x Heterozygous: 100% brown-eyed children It's important to note that these probabilities are based on the principles of Mendelian genetics and assume independent assortment and random mating.

I hope this helps! If you have further questions or need additional clarification, feel free to ask.