Question

Ген карих глаз доминирует над геном голубых глаз, а глухота – признак рецессивный, и обе пары генов находятся в разных хромосомах.Определите вероятность рождения глухих детей в семье, если оба родителя здоровые, кареглазые и гетерозиготны по обеим парам генов.

Answer 1

Глухие дети родятся с вероятностью1/4 ( из них кареглазых 3/4 и голубоглазых 1/4 по отношению к количеству глухих детей)

Answer 2

Probability of Having Deaf Children in a Family

In this scenario, both parents are healthy, have brown eyes, and are heterozygous for both pairs of genes. We are interested in determining the probability of having deaf children in this family.

The inheritance of deafness is a recessive trait, and both pairs of genes are located on different chromosomes. Given this information, we can calculate the probability using the principles of Mendelian genetics.

According to the provided information, the parents are heterozygous for the deafness gene. Let's denote the dominant allele for normal hearing as "A" and the recessive allele for deafness as "a". Since both parents are heterozygous, their genotypes can be represented as "Aa".

The Punnett square for the parents' genotypes "Aa" can be used to determine the probability of having deaf children.

The possible combinations from the Punnett square are as follows: - AA (normal hearing) - Aa (normal hearing) - Aa (normal hearing) - aa (deafness)

The probability of having a deaf child is the probability of the offspring inheriting the recessive allele "a", which is 25%.

Therefore, the probability of having deaf children in this family is 25%.

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