Question

В процессе фотосинтеза одно растение поглощает 280 г СО2 в день.Сколько образуется в листьях глюкозы и выделится кислорода за 5 дней?

Answer 1

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Answer 2

Photosynthesis Process

During the process of photosynthesis, one plant absorbs 280 g of CO2 per day. We can calculate the amount of glucose produced and the oxygen released over 5 days.

Glucose Production

To calculate the amount of glucose produced, we can use the general equation for photosynthesis, which shows the conversion of carbon dioxide and water into glucose and oxygen: 6 CO2 + 6 H2O + light energy → C6H12O6 + 6 O2

From the equation, we can see that for every 6 molecules of CO2, 1 molecule of glucose is produced. Therefore, the amount of glucose produced can be calculated as follows: 280 g of CO2 → (1/6) * 280 g of glucose per day = 46.67 g of glucose per day

Over 5 days, the total amount of glucose produced would be: 5 days * 46.67 g/day = 233.35 g of glucose

The amount of glucose produced in the leaves over 5 days is 233.35 g.

Oxygen Release

The equation for photosynthesis also shows that for every 6 molecules of CO2, 6 molecules of O2 are released. Therefore, the amount of oxygen released can be calculated as follows: 280 g of CO2 → 280 g of O2 per day

Over 5 days, the total amount of oxygen released would be: 5 days * 280 g/day = 1400 g of O2

The amount of oxygen released from the leaves over 5 days is 1400 g.

These calculations are based on the general stoichiometry of the photosynthesis process and the given amount of CO2 absorbed per day.

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