Question

Леворукость и фенилкетонурия – аутосомные рецессивные признаки, не сцепленных друг с другом. Здоровая леворукая женщина и здоровый праворукий мужчина имеют леворукую дочь и сына, который страдает фенилкетонурией. Чему равна вероятность рождения в этой семье здорового ребенка, хорошо владеющего левой рукой? ПОМОГИТЕ НУЖНО СРОЧНОО!!!!!!

Answer 1

Решение на фото.....:)

Answer 2

Autosomal Recessive Traits: Left-Handedness and Phenylketonuria

In this scenario, we are dealing with two autosomal recessive traits that are not linked to each other: left-handedness and phenylketonuria.

Autosomal Recessive Traits: Autosomal recessive traits are genetic conditions that appear only when an individual carries two copies of the mutated gene. In the case of phenylketonuria, it is caused by a mutation in the PAH gene, and in the case of left-handedness, the genetic basis is more complex and not fully understood.

Probability of Healthy Left-Handed Child in the Family

Given that the mother is healthy and left-handed (heterozygous for the left-handedness gene) and the father is healthy and right-handed (homozygous for the right-handedness gene), and they have a left-handed daughter and a son with phenylketonuria, we can calculate the probability of having a healthy child who is proficient with their left hand.

The probability can be calculated using Punnett squares and the principles of Mendelian genetics. In this case, the probability of having a healthy child who is proficient with their left hand would be 50%.

Conclusion

In this family, the probability of having a healthy child who is proficient with their left hand is 50%. This is based on the genetic inheritance patterns of autosomal recessive traits and the given information about the parents and their children.

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