Question

Полидактилии (шестипалость) доминирует над геном нормального строения кисти. 1.О6а родителя гетерозиготны. Определите вероятность рождения шестипалых детей. 2.В семье, где один из родителей имеет нормальное строение кисти, а второй- шестипалый, родился ребенок с нормальным строением кисти. Какова вероятность рождения следующего ребенка тоже без аномалии?

Answer 1

Ген         признак
А           полидактилия
а           норма
________________________

РЕШЕНИЕ

Р     Аа    х     Аа
G    А  а        А  а
F1    АА    Аа    Аа      аа
       полидактилия      норма
Ответ: вероятность рождения шестипалых детей 75%

Р    Аа        х      аа
G   А  а                а
F1       Аа        аа
           шест    норм.
Ответ: вероятность рождения ребенка без аномалий = 50%

Answer 2

Polidactyly (hexadactyly) is dominant over the normal hand structure. One of the parents is heterozygous. Determine the probability of having hexadactyl children.

To determine the probability of having hexadactyl (six-fingered) children when one of the parents is heterozygous for polidactyly, we need to consider the inheritance pattern of this trait.

Polidactyly is a dominant trait, which means that only one copy of the gene is needed for the trait to be expressed. In this case, the heterozygous parent has one copy of the polidactyly gene (P) and one copy of the normal hand structure gene (p).

The possible genotypes of the heterozygous parent are PP (polidactyl) and Pp (polidactyl). The genotype of the other parent is not specified, so we assume they have a normal hand structure and are homozygous for the normal hand structure gene (pp).

To determine the probability of having hexadactyl children, we need to consider the possible combinations of alleles that can be passed on from the parents to their offspring.

The Punnett square is a useful tool for visualizing the possible combinations of alleles. In this case, the Punnett square would look like this:

| | P | p | |------|-------|-------| | P | PP | Pp | | p | Pp | pp |

From the Punnett square, we can see that there are three possible genotypes for the offspring: PP (polidactyl), Pp (polidactyl), and pp (normal hand structure).

The probability of having hexadactyl children (PP or Pp) is 3/4 or 75%. This means that there is a 75% chance that the children will have hexadactyly.

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