Question

(x+1)^2×(x^2+2x)=12​

Answer 1

Ответ:

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Answer 2

To solve the equation $(x+1)^2 \cdot (x^2+2x) = 12$, follow these steps:

1. Expand the equation: $(x+1)^2 \cdot (x^2+2x) = 12$ \ $(x^2 + 2x + 1) \cdot (x^2 + 2x) = 12$

2. Distribute the terms: $x^2 \cdot (x^2 + 2x) + 2x \cdot (x^2 + 2x) + 1 \cdot (x^2 + 2x) = 12$ \ $x^4 + 2x^3 + 2x^3 + 4x^2 + x^2 + 2x = 12$

3. Combine like terms: $x^4 + 4x^3 + 5x^2 + 2x = 12$

4. Move all terms to one side of the equation to set it equal to zero: $x^4 + 4x^3 + 5x^2 + 2x - 12 = 0$

Now, the equation is a quartic equation in terms of $x$. Unfortunately, quartic equations generally do not have simple algebraic solutions like quadratic or cubic equations. You might need to use numerical methods or software to find approximate solutions for $x$, or you might look for factorizations or other methods specific to this equation to simplify it further.