Question

Log7(-10-x)=2 хелп плиз​

Answer 1

Ответ на фото.......

УДАЧИ!

Answer 2

To solve the equation Log₇(-10 - x) = 2, you'll need to use logarithmic properties to isolate x.

First, remember that Log₇(7) = 1, because any number raised to the power of 1 equals itself. So, you can rewrite the equation as:

Log₇(7^2) = Log₇(-10 - x)

Now, use the property of logarithms that allows you to bring the exponent down as a multiplier:

2 * Log₇(7) = Log₇(-10 - x)

Since Log₇(7) = 1, you have:

2 = Log₇(-10 - x)

Now, to eliminate the logarithm, you can rewrite the equation in exponential form. In exponential form, Log₇(a) = b can be written as 7^b = a. Applying that here:

7^2 = -10 - x

Now, calculate 7^2:

49 = -10 - x

Next, isolate x by moving -10 to the other side of the equation:

49 + 10 = -x

59 = -x

Finally, multiply both sides by -1 to solve for x:

x = -59

So, the solution to the equation Log₇(-10 - x) = 2 is x = -59.