Question

(Пж дайте ответ срочно)Хід роботи Задачі на моногібридне схрещування (повне домінування) Задача 1. У людини володіння переважно правою рукою – домі- нантна ознака, лівою - рецесивна. Чоловік-правша, мати якого була Aiвшею, одружився з жінкою-правшею, що мала двох сестер, одна з яких лівша. Яка ймовірність народження дитини-лівші? Дано Розв'язування Відповідь:

Answer 1

Ответ:

ймовірність народження дитині лівші становить 25%

Объяснение:

на фото:

Answer 2

Monohybrid Cross Problem with Complete Dominance

In this problem, we are dealing with a monohybrid cross with complete dominance. The given information includes the dominance of right-handedness over left-handedness in humans and the marriage of a right-handed man to a right-handed woman with a left-handed sister. We need to determine the probability of their child being left-handed.

Given Information: - Right-handedness is a dominant trait (denoted by D), and left-handedness is a recessive trait (denoted by d). - The father is right-handed (DD). - The mother is right-handed (DD). - One of the mother's sisters is left-handed (dd).

Probability of the Child Being Left-Handed: To determine the probability of their child being left-handed, we can use a Punnett square to visualize the possible combinations of alleles that the child could inherit from the parents.

The father's genotype: DD The mother's genotype: DD One of the mother's sisters' genotype: dd

By crossing the mother's genotype (DD) with the genotype of her sister (dd), we can determine the probability of the child being left-handed.

Punnett Square: ``` D D d Dd Dd d Dd Dd ```

From the Punnett square, we can see that all the offspring will be right-handed (DD). Therefore, the probability of the child being left-handed is 0%.

This result is based on the principles of Mendelian genetics and the laws of inheritance, which dictate the transmission of traits from parents to offspring.