Question

2. у людини ген альбiнiзму - рецесивна ознака. Здоровий чоловік, батьки якого теж були здоровими одружився з жінкою з альбiнiзмом. Яка ймовірність народження в них здорових дітей?​

Answer 1

Ответ:

ймовірність народження дитини з альбінізмом становить 0%

Объяснение:

на фото:

Answer 2

Understanding the Probability of Healthy Offspring in a Marriage with Albinism

In this scenario, we have a healthy man with both parents being healthy, marrying a woman with albinism. We need to calculate the probability of them having healthy children.

Understanding Albinism: Albinism is a recessive genetic trait, meaning that an individual must inherit two copies of the gene associated with albinism to express the condition. When a person has only one copy of the gene, they are considered carriers but do not exhibit the condition.

Genetic Makeup of the Parents: - The healthy man is homozygous dominant for the gene related to albinism (let's denote it as A). - The woman with albinism is homozygous recessive for the gene related to albinism (let's denote it as a).

Probability of Healthy Offspring: When these two individuals have children, each child will inherit one allele from each parent. The possible combinations are: 1. AA (healthy) 2. Aa (healthy, carrier) 3. aa (albino)

The Punnett square can be used to visualize the possible genetic combinations and their probabilities.

Punnett Square: ``` | | A | a | |-------|---------|---------| | A | AA | Aa | | a | Aa | aa | ```

Probability Calculation: - The probability of having a healthy child (AA or Aa) is 3/4 or 75%. - The probability of having a child with albinism (aa) is 1/4 or 25%.

Therefore, the probability of the couple having a healthy child is 75%.

This calculation assumes that the genetic traits are inherited independently and that there are no other genetic factors at play.